Base | Representation |
---|---|
bin | 11110010010100111000000… |
… | …000000110000100100010111 |
3 | 122110200201200022220112200012 |
4 | 132102213000000300210113 |
5 | 114430140003320410224 |
6 | 1151200305232110435 |
7 | 40026562202356415 |
oct | 3622470000604427 |
9 | 573621608815605 |
10 | 133220222044439 |
11 | 394a2419333422 |
12 | 12b36b7a99541b |
13 | 59447c7ab400a |
14 | 24c7c70b3c2b5 |
15 | 106056c73d80e |
hex | 7929c0030917 |
133220222044439 has 2 divisors, whose sum is σ = 133220222044440. Its totient is φ = 133220222044438.
The previous prime is 133220222044387. The next prime is 133220222044447. The reversal of 133220222044439 is 934440222022331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133220222044439 - 220 = 133220220995863 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133220222044396 and 133220222044405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133220222044939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66610111022219 + 66610111022220.
It is an arithmetic number, because the mean of its divisors is an integer number (66610111022220).
Almost surely, 2133220222044439 is an apocalyptic number.
133220222044439 is a deficient number, since it is larger than the sum of its proper divisors (1).
133220222044439 is an equidigital number, since it uses as much as digits as its factorization.
133220222044439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 497664, while the sum is 41.
The spelling of 133220222044439 in words is "one hundred thirty-three trillion, two hundred twenty billion, two hundred twenty-two million, forty-four thousand, four hundred thirty-nine".
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