Base | Representation |
---|---|
bin | 1100000111011100101111… |
… | …1001001000001100111000 |
3 | 1202011120201001110012101012 |
4 | 3001313023321020030320 |
5 | 3221232142232214134 |
6 | 44200032252413052 |
7 | 2543330261312360 |
oct | 301671371101470 |
9 | 52146631405335 |
10 | 13322114335544 |
11 | 4276971265663 |
12 | 15b1ab9177188 |
13 | 75836822b871 |
14 | 340b1818b9a0 |
15 | 18181350b6ce |
hex | c1dcbe48338 |
13322114335544 has 64 divisors (see below), whose sum is σ = 28645032404160. Its totient is φ = 5689981946880.
The previous prime is 13322114335489. The next prime is 13322114335547. The reversal of 13322114335544 is 44553341122331.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13322114335547) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18899354 + ... + 19591574.
It is an arithmetic number, because the mean of its divisors is an integer number (447578631315).
Almost surely, 213322114335544 is an apocalyptic number.
13322114335544 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
13322114335544 is an abundant number, since it is smaller than the sum of its proper divisors (15322918068616).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13322114335544 is a wasteful number, since it uses less digits than its factorization.
13322114335544 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 693408 (or 693404 counting only the distinct ones).
The product of its digits is 518400, while the sum is 41.
Adding to 13322114335544 its reverse (44553341122331), we get a palindrome (57875455457875).
The spelling of 13322114335544 in words is "thirteen trillion, three hundred twenty-two billion, one hundred fourteen million, three hundred thirty-five thousand, five hundred forty-four".
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