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133221213122321 is a prime number
BaseRepresentation
bin11110010010100111111011…
…000101011010111100010001
3122110200211020101210111221102
4132102213323011122330101
5114430144021024403241
61151200551434234145
740026625565400332
oct3622477305327421
9573624211714842
10133221213122321
11394a2887812955
1212b371b6885955
13594492521912c
1424c7d26606289
1510605c975b39b
hex7929fb15af11

133221213122321 has 2 divisors, whose sum is σ = 133221213122322. Its totient is φ = 133221213122320.

The previous prime is 133221213122297. The next prime is 133221213122323. The reversal of 133221213122321 is 123221312122331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 128206139524225 + 5015073598096 = 11322815^2 + 2239436^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133221213122321 is a prime.

Together with 133221213122323, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (133221213122323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66610606561160 + 66610606561161.

It is an arithmetic number, because the mean of its divisors is an integer number (66610606561161).

Almost surely, 2133221213122321 is an apocalyptic number.

It is an amenable number.

133221213122321 is a deficient number, since it is larger than the sum of its proper divisors (1).

133221213122321 is an equidigital number, since it uses as much as digits as its factorization.

133221213122321 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5184, while the sum is 29.

Adding to 133221213122321 its reverse (123221312122331), we get a palindrome (256442525244652).

The spelling of 133221213122321 in words is "one hundred thirty-three trillion, two hundred twenty-one billion, two hundred thirteen million, one hundred twenty-two thousand, three hundred twenty-one".