Base | Representation |
---|---|
bin | 11110010010101001000100… |
… | …011100111001001000001011 |
3 | 122110200221102011221012012122 |
4 | 132102221010130321020023 |
5 | 114430204031131341133 |
6 | 1151201313524401455 |
7 | 40030001232651161 |
oct | 3622510434711013 |
9 | 573627364835178 |
10 | 133222444012043 |
11 | 394a33595a7591 |
12 | 12b3749ab4628b |
13 | 5944a90237549 |
14 | 24c8001c97231 |
15 | 106064c849498 |
hex | 792a4473920b |
133222444012043 has 2 divisors, whose sum is σ = 133222444012044. Its totient is φ = 133222444012042.
The previous prime is 133222444011941. The next prime is 133222444012057. The reversal of 133222444012043 is 340210444222331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133222444012043 - 228 = 133222175576587 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 133222444011994 and 133222444012012.
It is not a weakly prime, because it can be changed into another prime (133222444012093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66611222006021 + 66611222006022.
It is an arithmetic number, because the mean of its divisors is an integer number (66611222006022).
Almost surely, 2133222444012043 is an apocalyptic number.
133222444012043 is a deficient number, since it is larger than the sum of its proper divisors (1).
133222444012043 is an equidigital number, since it uses as much as digits as its factorization.
133222444012043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 133222444012043 its reverse (340210444222331), we get a palindrome (473432888234374).
The spelling of 133222444012043 in words is "one hundred thirty-three trillion, two hundred twenty-two billion, four hundred forty-four million, twelve thousand, forty-three".
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