Base | Representation |
---|---|
bin | 11000110100001110… |
… | …10101011000010001 |
3 | 1021101111122011011122 |
4 | 30122013111120101 |
5 | 204241144011311 |
6 | 10042010452025 |
7 | 651104622062 |
oct | 143207253021 |
9 | 37344564148 |
10 | 13323032081 |
11 | 5717560217 |
12 | 26b9a34015 |
13 | 13442a5048 |
14 | 905616569 |
15 | 52e9b00db |
hex | 31a1d5611 |
13323032081 has 2 divisors, whose sum is σ = 13323032082. Its totient is φ = 13323032080.
The previous prime is 13323032057. The next prime is 13323032083. The reversal of 13323032081 is 18023032331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7564650625 + 5758381456 = 86975^2 + 75884^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13323032081 is a prime.
It is a super-2 number, since 2×133230320812 (a number of 21 digits) contains 22 as substring.
Together with 13323032083, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13323032081.
It is not a weakly prime, because it can be changed into another prime (13323032083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6661516040 + 6661516041.
It is an arithmetic number, because the mean of its divisors is an integer number (6661516041).
Almost surely, 213323032081 is an apocalyptic number.
It is an amenable number.
13323032081 is a deficient number, since it is larger than the sum of its proper divisors (1).
13323032081 is an equidigital number, since it uses as much as digits as its factorization.
13323032081 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 26.
The spelling of 13323032081 in words is "thirteen billion, three hundred twenty-three million, thirty-two thousand, eighty-one".
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