Base | Representation |
---|---|
bin | 1100000111100000011111… |
… | …1001101101011100000110 |
3 | 1202011200022012220012102112 |
4 | 3001320013321231130012 |
5 | 3221241223001333110 |
6 | 44200320215341022 |
7 | 2543364234664130 |
oct | 301700771553406 |
9 | 52150265805375 |
10 | 13323121121030 |
11 | 42773385a3486 |
12 | 15b213a381772 |
13 | 7584989a3416 |
14 | 340bb1b84050 |
15 | 181871acd405 |
hex | c1e07e6d706 |
13323121121030 has 16 divisors (see below), whose sum is σ = 27407563449120. Its totient is φ = 4567927241472.
The previous prime is 13323121120997. The next prime is 13323121121041. The reversal of 13323121121030 is 3012112132331.
13323121121030 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13323121120987 and 13323121121005.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 95165150795 + ... + 95165150934.
It is an arithmetic number, because the mean of its divisors is an integer number (1712972715570).
Almost surely, 213323121121030 is an apocalyptic number.
13323121121030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13323121121030 is an abundant number, since it is smaller than the sum of its proper divisors (14084442328090).
13323121121030 is a wasteful number, since it uses less digits than its factorization.
13323121121030 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 190330301743.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 13323121121030 its reverse (3012112132331), we get a palindrome (16335233253361).
The spelling of 13323121121030 in words is "thirteen trillion, three hundred twenty-three billion, one hundred twenty-one million, one hundred twenty-one thousand, thirty".
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