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133231321304010 = 23453753978571009
BaseRepresentation
bin11110010010110001010101…
…100101000100101111001010
3122110201210022212010100110000
4132102301111211010233022
5114430330221223212020
61151205342443503430
740030434225461646
oct3622612545045712
9573653285110400
10133231321304010
11394a70a45a7416
1212b39157b27b76
135945876453127
1424c8604c89c26
1510609bbd88090
hex792c55944bca

133231321304010 has 640 divisors, whose sum is σ = 379550850719040. Its totient is φ = 33493854191616.

The previous prime is 133231321303991. The next prime is 133231321304017. The reversal of 133231321304010 is 10403123132331.

133231321304010 is a `hidden beast` number, since 1 + 3 + 3 + 2 + 31 + 321 + 304 + 0 + 1 + 0 = 666.

It can be written as a sum of positive squares in 32 ways, for example, as 20395493402769 + 112835827901241 = 4516137^2 + 10622421^2 .

It is a Harshad number since it is a multiple of its sum of digits (27).

It is not an unprimeable number, because it can be changed into a prime (133231321304017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 319 ways as a sum of consecutive naturals, for example, 132042934386 + ... + 132042935394.

Almost surely, 2133231321304010 is an apocalyptic number.

133231321304010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 133231321304010, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (189775425359520).

133231321304010 is an abundant number, since it is smaller than the sum of its proper divisors (246319529415030).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133231321304010 is a wasteful number, since it uses less digits than its factorization.

133231321304010 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2072 (or 2063 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 27.

Adding to 133231321304010 its reverse (10403123132331), we get a palindrome (143634444436341).

It can be divided in two parts, 133231321 and 304010, that added together give a palindrome (133535331).

The spelling of 133231321304010 in words is "one hundred thirty-three trillion, two hundred thirty-one billion, three hundred twenty-one million, three hundred four thousand, ten".