Base | Representation |
---|---|
bin | 10011011000110100100… |
… | …101001000001111000011 |
3 | 11201100221210220200120112 |
4 | 103120310211020033003 |
5 | 133312043413310201 |
6 | 2500021004301535 |
7 | 165154116142004 |
oct | 23306445101703 |
9 | 4640853820515 |
10 | 1332322010051 |
11 | 47404204a79a |
12 | 196267b418ab |
13 | 9883956c986 |
14 | 486b01511ab |
15 | 249cb81c0bb |
hex | 136349483c3 |
1332322010051 has 2 divisors, whose sum is σ = 1332322010052. Its totient is φ = 1332322010050.
The previous prime is 1332322009979. The next prime is 1332322010053. The reversal of 1332322010051 is 1500102232331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1332322010051 - 234 = 1315142140867 is a prime.
It is a super-3 number, since 3×13323220100513 (a number of 37 digits) contains 333 as substring.
Together with 1332322010053, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1332322009999 and 1332322010026.
It is not a weakly prime, because it can be changed into another prime (1332322010053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666161005025 + 666161005026.
It is an arithmetic number, because the mean of its divisors is an integer number (666161005026).
Almost surely, 21332322010051 is an apocalyptic number.
1332322010051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1332322010051 is an equidigital number, since it uses as much as digits as its factorization.
1332322010051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 23.
Adding to 1332322010051 its reverse (1500102232331), we get a palindrome (2832424242382).
The spelling of 1332322010051 in words is "one trillion, three hundred thirty-two billion, three hundred twenty-two million, ten thousand, fifty-one".
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