Base | Representation |
---|---|
bin | 10011011000110100101… |
… | …001010100110100000011 |
3 | 11201100221212222120121211 |
4 | 103120310221110310003 |
5 | 133312044204011042 |
6 | 2500021044030551 |
7 | 165154131403201 |
oct | 23306451246403 |
9 | 4640855876554 |
10 | 1332323110147 |
11 | 474042731267 |
12 | 196268392457 |
13 | 98839866613 |
14 | 486b035a071 |
15 | 249cb988017 |
hex | 13634a54d03 |
1332323110147 has 2 divisors, whose sum is σ = 1332323110148. Its totient is φ = 1332323110146.
The previous prime is 1332323110123. The next prime is 1332323110171. The reversal of 1332323110147 is 7410113232331.
It is a balanced prime because it is at equal distance from previous prime (1332323110123) and next prime (1332323110171).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1332323110147 is a prime.
It is not a weakly prime, because it can be changed into another prime (1332323110187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666161555073 + 666161555074.
It is an arithmetic number, because the mean of its divisors is an integer number (666161555074).
Almost surely, 21332323110147 is an apocalyptic number.
1332323110147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1332323110147 is an equidigital number, since it uses as much as digits as its factorization.
1332323110147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 31.
Adding to 1332323110147 its reverse (7410113232331), we get a palindrome (8742436342478).
The spelling of 1332323110147 in words is "one trillion, three hundred thirty-two billion, three hundred twenty-three million, one hundred ten thousand, one hundred forty-seven".
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