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133234314310169 is a prime number
BaseRepresentation
bin11110010010110100000111…
…111110011111001000011001
3122110202002001102222211000222
4132102310013332133020121
5114430402333430411134
61151210555442205425
740030601340555302
oct3622640776371031
9573662042884028
10133234314310169
11394a83a0020226
1212b39852353875
135945c325591a7
1424c880a5917a9
151060ae49e9a2e
hex792d07f9f219

133234314310169 has 2 divisors, whose sum is σ = 133234314310170. Its totient is φ = 133234314310168.

The previous prime is 133234314310091. The next prime is 133234314310171. The reversal of 133234314310169 is 961013413432331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120773506090000 + 12460808220169 = 10989700^2 + 3529987^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133234314310169 is a prime.

It is a super-2 number, since 2×1332343143101692 (a number of 29 digits) contains 22 as substring.

Together with 133234314310171, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (133234314310969) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66617157155084 + 66617157155085.

It is an arithmetic number, because the mean of its divisors is an integer number (66617157155085).

Almost surely, 2133234314310169 is an apocalyptic number.

It is an amenable number.

133234314310169 is a deficient number, since it is larger than the sum of its proper divisors (1).

133234314310169 is an equidigital number, since it uses as much as digits as its factorization.

133234314310169 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 419904, while the sum is 44.

The spelling of 133234314310169 in words is "one hundred thirty-three trillion, two hundred thirty-four billion, three hundred fourteen million, three hundred ten thousand, one hundred sixty-nine".