Base | Representation |
---|---|
bin | 1100000111100100001110… |
… | …0001101000110101100111 |
3 | 1202011202212221011212010211 |
4 | 3001321003201220311213 |
5 | 3221300300042144222 |
6 | 44201003352000251 |
7 | 2543431102410535 |
oct | 301710341506547 |
9 | 52152787155124 |
10 | 13324121443687 |
11 | 427780121771a |
12 | 15b2379390087 |
13 | 7585c7cc4412 |
14 | 340c68977155 |
15 | 1818ce825277 |
hex | c1e43868d67 |
13324121443687 has 2 divisors, whose sum is σ = 13324121443688. Its totient is φ = 13324121443686.
The previous prime is 13324121443669. The next prime is 13324121443691. The reversal of 13324121443687 is 78634412142331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13324121443687 is a prime.
It is a super-2 number, since 2×133241214436872 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13324121443687.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13324121443657) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6662060721843 + 6662060721844.
It is an arithmetic number, because the mean of its divisors is an integer number (6662060721844).
Almost surely, 213324121443687 is an apocalyptic number.
13324121443687 is a deficient number, since it is larger than the sum of its proper divisors (1).
13324121443687 is an equidigital number, since it uses as much as digits as its factorization.
13324121443687 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2322432, while the sum is 49.
The spelling of 13324121443687 in words is "thirteen trillion, three hundred twenty-four billion, one hundred twenty-one million, four hundred forty-three thousand, six hundred eighty-seven".
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