Base | Representation |
---|---|
bin | 111110000010111001… |
… | …1101011100110101011 |
3 | 110201220211020110012221 |
4 | 1330011303223212223 |
5 | 4140334300421303 |
6 | 141113230014511 |
7 | 12424563246013 |
oct | 1740563534653 |
9 | 421824213187 |
10 | 133241420203 |
11 | 51564343101 |
12 | 219a6347437 |
13 | c7455b6458 |
14 | 663db96c43 |
15 | 36ec6e44bd |
hex | 1f05ceb9ab |
133241420203 has 2 divisors, whose sum is σ = 133241420204. Its totient is φ = 133241420202.
The previous prime is 133241420071. The next prime is 133241420209. The reversal of 133241420203 is 302024142331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133241420203 is a prime.
It is a super-2 number, since 2×1332414202032 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133241420209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66620710101 + 66620710102.
It is an arithmetic number, because the mean of its divisors is an integer number (66620710102).
Almost surely, 2133241420203 is an apocalyptic number.
133241420203 is a deficient number, since it is larger than the sum of its proper divisors (1).
133241420203 is an equidigital number, since it uses as much as digits as its factorization.
133241420203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 133241420203 its reverse (302024142331), we get a palindrome (435265562534).
The spelling of 133241420203 in words is "one hundred thirty-three billion, two hundred forty-one million, four hundred twenty thousand, two hundred three".
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