Base | Representation |
---|---|
bin | 111110000010111101… |
… | …0001010100111111011 |
3 | 110201220221102211001221 |
4 | 1330011322022213323 |
5 | 4140340214320443 |
6 | 141113330252511 |
7 | 12424613556031 |
oct | 1740572124773 |
9 | 421827384057 |
10 | 133243120123 |
11 | 515652a42a3 |
12 | 219a6a27137 |
13 | c745a60119 |
14 | 66400ba551 |
15 | 36ec92ceed |
hex | 1f05e8a9fb |
133243120123 has 2 divisors, whose sum is σ = 133243120124. Its totient is φ = 133243120122.
The previous prime is 133243120117. The next prime is 133243120147. The reversal of 133243120123 is 321021342331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133243120123 - 25 = 133243120091 is a prime.
It is a super-2 number, since 2×1332431201232 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133243120193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66621560061 + 66621560062.
It is an arithmetic number, because the mean of its divisors is an integer number (66621560062).
Almost surely, 2133243120123 is an apocalyptic number.
133243120123 is a deficient number, since it is larger than the sum of its proper divisors (1).
133243120123 is an equidigital number, since it uses as much as digits as its factorization.
133243120123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 133243120123 its reverse (321021342331), we get a palindrome (454264462454).
The spelling of 133243120123 in words is "one hundred thirty-three billion, two hundred forty-three million, one hundred twenty thousand, one hundred twenty-three".
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