Base | Representation |
---|---|
bin | 11110010010111100100110… |
… | …001001011011100101001011 |
3 | 122110202221112100221121001112 |
4 | 132102330212021123211023 |
5 | 114431030001032232113 |
6 | 1151215102215440535 |
7 | 40031342631402026 |
oct | 3622744611334513 |
9 | 573687470847045 |
10 | 133243410430283 |
11 | 395012385a296a |
12 | 12b3b57068614b |
13 | 5946a51bc1c9a |
14 | 24c90306681bd |
15 | 1060e783615a8 |
hex | 792f2625b94b |
133243410430283 has 2 divisors, whose sum is σ = 133243410430284. Its totient is φ = 133243410430282.
The previous prime is 133243410430231. The next prime is 133243410430313. The reversal of 133243410430283 is 382034014342331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133243410430283 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133243410430283.
It is not a weakly prime, because it can be changed into another prime (133243410430883) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66621705215141 + 66621705215142.
It is an arithmetic number, because the mean of its divisors is an integer number (66621705215142).
Almost surely, 2133243410430283 is an apocalyptic number.
133243410430283 is a deficient number, since it is larger than the sum of its proper divisors (1).
133243410430283 is an equidigital number, since it uses as much as digits as its factorization.
133243410430283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 497664, while the sum is 41.
The spelling of 133243410430283 in words is "one hundred thirty-three trillion, two hundred forty-three billion, four hundred ten million, four hundred thirty thousand, two hundred eighty-three".
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