Base | Representation |
---|---|
bin | 10011011000111100010… |
… | …110010001101010000011 |
3 | 11201101021220010211201021 |
4 | 103120330112101222003 |
5 | 133312330244143321 |
6 | 2500041541450311 |
7 | 165160260652555 |
oct | 23307426215203 |
9 | 4641256124637 |
10 | 1332452334211 |
11 | 4740a9673209 |
12 | 1962a3710997 |
13 | 9885a56cb6b |
14 | 486c35974d5 |
15 | 249d7eb1941 |
hex | 1363c591a83 |
1332452334211 has 2 divisors, whose sum is σ = 1332452334212. Its totient is φ = 1332452334210.
The previous prime is 1332452334181. The next prime is 1332452334217. The reversal of 1332452334211 is 1124332542331.
It is a strong prime.
It is an emirp because it is prime and its reverse (1124332542331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1332452334211 - 211 = 1332452332163 is a prime.
It is not a weakly prime, because it can be changed into another prime (1332452334217) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666226167105 + 666226167106.
It is an arithmetic number, because the mean of its divisors is an integer number (666226167106).
Almost surely, 21332452334211 is an apocalyptic number.
1332452334211 is a deficient number, since it is larger than the sum of its proper divisors (1).
1332452334211 is an equidigital number, since it uses as much as digits as its factorization.
1332452334211 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 51840, while the sum is 34.
Adding to 1332452334211 its reverse (1124332542331), we get a palindrome (2456784876542).
The spelling of 1332452334211 in words is "one trillion, three hundred thirty-two billion, four hundred fifty-two million, three hundred thirty-four thousand, two hundred eleven".
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