Base | Representation |
---|---|
bin | 10011011000111111001… |
… | …100010011011001101011 |
3 | 11201101102012221010121121 |
4 | 103120333030103121223 |
5 | 133312430003122223 |
6 | 2500050404320111 |
7 | 165161410362322 |
oct | 23307714233153 |
9 | 4641365833547 |
10 | 1332500051563 |
11 | 4741235a4a3a |
12 | 1962b76a3037 |
13 | 98867409295 |
14 | 486c9a590b9 |
15 | 249dc28a15d |
hex | 1363f31366b |
1332500051563 has 2 divisors, whose sum is σ = 1332500051564. Its totient is φ = 1332500051562.
The previous prime is 1332500051503. The next prime is 1332500051581. The reversal of 1332500051563 is 3651500052331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1332500051563 is a prime.
It is a super-3 number, since 3×13325000515633 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1332500051503) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666250025781 + 666250025782.
It is an arithmetic number, because the mean of its divisors is an integer number (666250025782).
Almost surely, 21332500051563 is an apocalyptic number.
1332500051563 is a deficient number, since it is larger than the sum of its proper divisors (1).
1332500051563 is an equidigital number, since it uses as much as digits as its factorization.
1332500051563 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40500, while the sum is 34.
The spelling of 1332500051563 in words is "one trillion, three hundred thirty-two billion, five hundred million, fifty-one thousand, five hundred sixty-three".
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