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133252105434552 = 233213142363360507
BaseRepresentation
bin11110010011000100101100…
…011010001111010110111000
3122110210202222100010120120200
4132103010230122033112320
5114431200302442401202
61151223101103522200
740032101251615506
oct3623045432172670
9573722870116520
10133252105434552
113950499a708305
1212b411985b9360
135947809415620
1424c9617369676
1510612d6893e1c
hex79312c68f5b8

133252105434552 has 48 divisors (see below), whose sum is σ = 388651974186840. Its totient is φ = 41000647825728.

The previous prime is 133252105434509. The next prime is 133252105434601. The reversal of 133252105434552 is 255434501252331.

133252105434552 is a `hidden beast` number, since 1 + 3 + 3 + 2 + 5 + 2 + 10 + 54 + 34 + 552 = 666.

133252105434552 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×1332521054345522 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133252105434498 and 133252105434507.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 71181679318 + ... + 71181681189.

Almost surely, 2133252105434552 is an apocalyptic number.

133252105434552 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

133252105434552 is an abundant number, since it is smaller than the sum of its proper divisors (255399868752288).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133252105434552 is a wasteful number, since it uses less digits than its factorization.

133252105434552 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 142363360532 (or 142363360525 counting only the distinct ones).

The product of its (nonzero) digits is 2160000, while the sum is 45.

Adding to 133252105434552 its reverse (255434501252331), we get a palindrome (388686606686883).

The spelling of 133252105434552 in words is "one hundred thirty-three trillion, two hundred fifty-two billion, one hundred five million, four hundred thirty-four thousand, five hundred fifty-two".

Divisors: 1 2 3 4 6 8 9 12 13 18 24 26 36 39 52 72 78 104 117 156 234 312 468 936 142363360507 284726721014 427090081521 569453442028 854180163042 1138906884056 1281270244563 1708360326084 1850723686591 2562540489126 3416720652168 3701447373182 5125080978252 5552171059773 7402894746364 10250161956504 11104342119546 14805789492728 16656513179319 22208684239092 33313026358638 44417368478184 66626052717276 133252105434552