Base | Representation |
---|---|
bin | 10011011001011010000… |
… | …111100100010101100001 |
3 | 11201102120200222002011112 |
4 | 103121122013210111201 |
5 | 133314341124420131 |
6 | 2500203302553105 |
7 | 165205534212566 |
oct | 23313207442541 |
9 | 4642520862145 |
10 | 1332951795041 |
11 | 4743355a1559 |
12 | 196402a38795 |
13 | 98909b96709 |
14 | 4872da4c86d |
15 | 24a16c7002b |
hex | 1365a1e4561 |
1332951795041 has 2 divisors, whose sum is σ = 1332951795042. Its totient is φ = 1332951795040.
The previous prime is 1332951794963. The next prime is 1332951795047. The reversal of 1332951795041 is 1405971592331.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1231869130816 + 101082664225 = 1109896^2 + 317935^2 .
It is an emirp because it is prime and its reverse (1405971592331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1332951795041 - 210 = 1332951794017 is a prime.
It is not a weakly prime, because it can be changed into another prime (1332951795047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666475897520 + 666475897521.
It is an arithmetic number, because the mean of its divisors is an integer number (666475897521).
Almost surely, 21332951795041 is an apocalyptic number.
It is an amenable number.
1332951795041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1332951795041 is an equidigital number, since it uses as much as digits as its factorization.
1332951795041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1020600, while the sum is 50.
The spelling of 1332951795041 in words is "one trillion, three hundred thirty-two billion, nine hundred fifty-one million, seven hundred ninety-five thousand, forty-one".
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