Base | Representation |
---|---|
bin | 11110010011110010010110… |
… | …101000111110000111010111 |
3 | 122110222110112002212110200201 |
4 | 132103302112220332013113 |
5 | 114433001204333234424 |
6 | 1151301410024121331 |
7 | 40035455216361301 |
oct | 3623622650760727 |
9 | 573873462773621 |
10 | 133301132321239 |
11 | 39523769050983 |
12 | 12b4a79b606247 |
13 | 594c3206a004c |
14 | 24cbb4874a971 |
15 | 1062705ab8d44 |
hex | 793c96a3e1d7 |
133301132321239 has 2 divisors, whose sum is σ = 133301132321240. Its totient is φ = 133301132321238.
The previous prime is 133301132321219. The next prime is 133301132321339. The reversal of 133301132321239 is 932123231103331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133301132321239 - 213 = 133301132313047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133301132321198 and 133301132321207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133301132321209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66650566160619 + 66650566160620.
It is an arithmetic number, because the mean of its divisors is an integer number (66650566160620).
Almost surely, 2133301132321239 is an apocalyptic number.
133301132321239 is a deficient number, since it is larger than the sum of its proper divisors (1).
133301132321239 is an equidigital number, since it uses as much as digits as its factorization.
133301132321239 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 52488, while the sum is 37.
The spelling of 133301132321239 in words is "one hundred thirty-three trillion, three hundred one billion, one hundred thirty-two million, three hundred twenty-one thousand, two hundred thirty-nine".
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