Base | Representation |
---|---|
bin | 11000110101000100… |
… | …11000001100111111 |
3 | 1021101222222100002000 |
4 | 30122202120030333 |
5 | 204300002342120 |
6 | 10042422433343 |
7 | 651222110043 |
oct | 143242301477 |
9 | 37358870060 |
10 | 13330121535 |
11 | 5720562675 |
12 | 2700292853 |
13 | 13458b7ba3 |
14 | 906540023 |
15 | 530410990 |
hex | 31a89833f |
13330121535 has 32 divisors (see below), whose sum is σ = 24338489280. Its totient is φ = 6917249664.
The previous prime is 13330121533. The next prime is 13330121573. The reversal of 13330121535 is 53512103331.
13330121535 is a `hidden beast` number, since 1 + 3 + 3 + 3 + 0 + 121 + 535 = 666.
13330121535 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13330121535 - 21 = 13330121533 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 13330121499 and 13330121508.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13330121533) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1329352 + ... + 1339341.
It is an arithmetic number, because the mean of its divisors is an integer number (760577790).
Almost surely, 213330121535 is an apocalyptic number.
13330121535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13330121535 is a deficient number, since it is larger than the sum of its proper divisors (11008367745).
13330121535 is a wasteful number, since it uses less digits than its factorization.
13330121535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2668744 (or 2668738 counting only the distinct ones).
The product of its (nonzero) digits is 4050, while the sum is 27.
Adding to 13330121535 its reverse (53512103331), we get a palindrome (66842224866).
The spelling of 13330121535 in words is "thirteen billion, three hundred thirty million, one hundred twenty-one thousand, five hundred thirty-five".
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