Base | Representation |
---|---|
bin | 11110010011110010011100… |
… | …011101100101101111011001 |
3 | 122110222110202220200010021211 |
4 | 132103302130131211233121 |
5 | 114433001404340013423 |
6 | 1151301423433503121 |
7 | 40035460513551256 |
oct | 3623623435455731 |
9 | 573873686603254 |
10 | 133301230001113 |
11 | 395238091a8249 |
12 | 12b4a808271aa1 |
13 | 594c3379b07a5 |
14 | 24cbb576d642d |
15 | 106270e46110d |
hex | 793c9c765bd9 |
133301230001113 has 2 divisors, whose sum is σ = 133301230001114. Its totient is φ = 133301230001112.
The previous prime is 133301230001099. The next prime is 133301230001213. The reversal of 133301230001113 is 311100032103331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 82202365168704 + 51098864832409 = 9066552^2 + 7148347^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133301230001113 is a prime.
It is not a weakly prime, because it can be changed into another prime (133301230001213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66650615000556 + 66650615000557.
It is an arithmetic number, because the mean of its divisors is an integer number (66650615000557).
Almost surely, 2133301230001113 is an apocalyptic number.
It is an amenable number.
133301230001113 is a deficient number, since it is larger than the sum of its proper divisors (1).
133301230001113 is an equidigital number, since it uses as much as digits as its factorization.
133301230001113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 133301230001113 its reverse (311100032103331), we get a palindrome (444401262104444).
The spelling of 133301230001113 in words is "one hundred thirty-three trillion, three hundred one billion, two hundred thirty million, one thousand, one hundred thirteen".
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