Base | Representation |
---|---|
bin | 11110010011110010011100… |
… | …011101100101101111011010 |
3 | 122110222110202220200010021212 |
4 | 132103302130131211233122 |
5 | 114433001404340013424 |
6 | 1151301423433503122 |
7 | 40035460513551260 |
oct | 3623623435455732 |
9 | 573873686603255 |
10 | 133301230001114 |
11 | 395238091a824a |
12 | 12b4a808271aa2 |
13 | 594c3379b07a6 |
14 | 24cbb576d6430 |
15 | 106270e46110e |
hex | 793c9c765bda |
133301230001114 has 32 divisors (see below), whose sum is σ = 232004648131200. Its totient is φ = 56262149856000.
The previous prime is 133301230001113. The next prime is 133301230001213. The reversal of 133301230001114 is 411100032103331.
It is a self number, because there is not a number n which added to its sum of digits gives 133301230001114.
It is not an unprimeable number, because it can be changed into a prime (133301230001113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 212801459 + ... + 213426950.
It is an arithmetic number, because the mean of its divisors is an integer number (7250145254100).
Almost surely, 2133301230001114 is an apocalyptic number.
133301230001114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
133301230001114 is a deficient number, since it is larger than the sum of its proper divisors (98703418130086).
133301230001114 is a wasteful number, since it uses less digits than its factorization.
133301230001114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 426228758.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 133301230001114 its reverse (411100032103331), we get a palindrome (544401262104445).
The spelling of 133301230001114 in words is "one hundred thirty-three trillion, three hundred one billion, two hundred thirty million, one thousand, one hundred fourteen".
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