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1333013100229 is a prime number
BaseRepresentation
bin10011011001011101110…
…001011011011011000101
311201102201222022201002001
4103121131301123123011
5133320002323201404
62500213332545301
7165210210254116
oct23313561333305
94642658281061
101333013100229
11474367163aa8
1219641b482231
13989197ac785
1448737c4a20d
1524a1c32e7a4
hex1365dc5b6c5

1333013100229 has 2 divisors, whose sum is σ = 1333013100230. Its totient is φ = 1333013100228.

The previous prime is 1333013100193. The next prime is 1333013100239. The reversal of 1333013100229 is 9220013103331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1234732104225 + 98280996004 = 1111185^2 + 313498^2 .

It is an emirp because it is prime and its reverse (9220013103331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1333013100229 - 229 = 1332476229317 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1333013100197 and 1333013100206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1333013100239) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666506550114 + 666506550115.

It is an arithmetic number, because the mean of its divisors is an integer number (666506550115).

Almost surely, 21333013100229 is an apocalyptic number.

It is an amenable number.

1333013100229 is a deficient number, since it is larger than the sum of its proper divisors (1).

1333013100229 is an equidigital number, since it uses as much as digits as its factorization.

1333013100229 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2916, while the sum is 28.

The spelling of 1333013100229 in words is "one trillion, three hundred thirty-three billion, thirteen million, one hundred thousand, two hundred twenty-nine".