Base | Representation |
---|---|
bin | 1100000111111011001111… |
… | …1110111100110111111110 |
3 | 1202012100211202010201222212 |
4 | 3001332303332330313332 |
5 | 3221400430101042142 |
6 | 44203505015140422 |
7 | 2544040224113666 |
oct | 301766376746776 |
9 | 52170752121885 |
10 | 13330303143422 |
11 | 427a393671181 |
12 | 15b3603674712 |
13 | 75907190a905 |
14 | 3412939631a6 |
15 | 181b4239ed82 |
hex | c1fb3fbcdfe |
13330303143422 has 4 divisors (see below), whose sum is σ = 19995454715136. Its totient is φ = 6665151571710.
The previous prime is 13330303143407. The next prime is 13330303143449. The reversal of 13330303143422 is 22434130303331.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×133303031434223 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3332575785854 + ... + 3332575785857.
It is an arithmetic number, because the mean of its divisors is an integer number (4998863678784).
Almost surely, 213330303143422 is an apocalyptic number.
13330303143422 is a deficient number, since it is larger than the sum of its proper divisors (6665151571714).
13330303143422 is an equidigital number, since it uses as much as digits as its factorization.
13330303143422 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6665151571713.
The product of its (nonzero) digits is 46656, while the sum is 32.
Adding to 13330303143422 its reverse (22434130303331), we get a palindrome (35764433446753).
The spelling of 13330303143422 in words is "thirteen trillion, three hundred thirty billion, three hundred three million, one hundred forty-three thousand, four hundred twenty-two".
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