Base | Representation |
---|---|
bin | 1100000111111011010110… |
… | …1101110101111100001111 |
3 | 1202012100220202211121222011 |
4 | 3001332311231311330033 |
5 | 3221401010021304012 |
6 | 44203511534202051 |
7 | 2544041026155655 |
oct | 301766555657417 |
9 | 52170822747864 |
10 | 13330332213007 |
11 | 427a3a9016627 |
12 | 15b3611353327 |
13 | 759077948254 |
14 | 34129776cdd5 |
15 | 181b44be31a7 |
hex | c1fb5b75f0f |
13330332213007 has 2 divisors, whose sum is σ = 13330332213008. Its totient is φ = 13330332213006.
The previous prime is 13330332212987. The next prime is 13330332213031. The reversal of 13330332213007 is 70031223303331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13330332213007 - 243 = 4534239190799 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13330332213007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13330332213607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665166106503 + 6665166106504.
It is an arithmetic number, because the mean of its divisors is an integer number (6665166106504).
Almost surely, 213330332213007 is an apocalyptic number.
13330332213007 is a deficient number, since it is larger than the sum of its proper divisors (1).
13330332213007 is an equidigital number, since it uses as much as digits as its factorization.
13330332213007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20412, while the sum is 31.
Adding to 13330332213007 its reverse (70031223303331), we get a palindrome (83361555516338).
The spelling of 13330332213007 in words is "thirteen trillion, three hundred thirty billion, three hundred thirty-two million, two hundred thirteen thousand, seven".
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