Base | Representation |
---|---|
bin | 111110000100110001… |
… | …1010010110100011001 |
3 | 110202002012102200111202 |
4 | 1330021203102310121 |
5 | 4141001340430431 |
6 | 141123352203545 |
7 | 12426255200264 |
oct | 1741143226431 |
9 | 422065380452 |
10 | 133304233241 |
11 | 51596845503 |
12 | 21a033995b5 |
13 | c75560992a |
14 | 6648267cdb |
15 | 3702ea08cb |
hex | 1f098d2d19 |
133304233241 has 2 divisors, whose sum is σ = 133304233242. Its totient is φ = 133304233240.
The previous prime is 133304233219. The next prime is 133304233243. The reversal of 133304233241 is 142332403331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 83755254025 + 49548979216 = 289405^2 + 222596^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133304233241 is a prime.
Together with 133304233243, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (133304233243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66652116620 + 66652116621.
It is an arithmetic number, because the mean of its divisors is an integer number (66652116621).
Almost surely, 2133304233241 is an apocalyptic number.
It is an amenable number.
133304233241 is a deficient number, since it is larger than the sum of its proper divisors (1).
133304233241 is an equidigital number, since it uses as much as digits as its factorization.
133304233241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 133304233241 its reverse (142332403331), we get a palindrome (275636636572).
The spelling of 133304233241 in words is "one hundred thirty-three billion, three hundred four million, two hundred thirty-three thousand, two hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •