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133305022434119 is a prime number
BaseRepresentation
bin11110010011110101111110…
…100000100100101101000111
3122110222211120012210200100112
4132103311332200210231013
5114433032141220342434
61151303252030503235
740035653503653254
oct3623657640445507
9573884505720315
10133305022434119
1139525384a002a8
1212b4b4a6364b1b
13594c7c05c88a3
1424cbdd725842b
151062882384dce
hex793d7e824b47

133305022434119 has 2 divisors, whose sum is σ = 133305022434120. Its totient is φ = 133305022434118.

The previous prime is 133305022434083. The next prime is 133305022434131. The reversal of 133305022434119 is 911434220503331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 133305022434119 - 212 = 133305022430023 is a prime.

It is a super-2 number, since 2×1333050224341192 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133305022434319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66652511217059 + 66652511217060.

It is an arithmetic number, because the mean of its divisors is an integer number (66652511217060).

Almost surely, 2133305022434119 is an apocalyptic number.

133305022434119 is a deficient number, since it is larger than the sum of its proper divisors (1).

133305022434119 is an equidigital number, since it uses as much as digits as its factorization.

133305022434119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 233280, while the sum is 41.

The spelling of 133305022434119 in words is "one hundred thirty-three trillion, three hundred five billion, twenty-two million, four hundred thirty-four thousand, one hundred nineteen".