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133305522000451 is a prime number
BaseRepresentation
bin11110010011110110011100…
…010010010001001001000011
3122110222212212000211021112021
4132103312130102101021003
5114433034202113003301
61151303413354142311
740036002051133003
oct3623663422211103
9573885760737467
10133305522000451
11395256109a0939
1212b4b605721997
13594c86cc5b478
1424cc04373a003
1510628b11648a1
hex793d9c491243

133305522000451 has 2 divisors, whose sum is σ = 133305522000452. Its totient is φ = 133305522000450.

The previous prime is 133305522000407. The next prime is 133305522000467. The reversal of 133305522000451 is 154000225503331.

It is a strong prime.

It is an emirp because it is prime and its reverse (154000225503331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133305522000451 - 27 = 133305522000323 is a prime.

It is not a weakly prime, because it can be changed into another prime (133305522000551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66652761000225 + 66652761000226.

It is an arithmetic number, because the mean of its divisors is an integer number (66652761000226).

Almost surely, 2133305522000451 is an apocalyptic number.

133305522000451 is a deficient number, since it is larger than the sum of its proper divisors (1).

133305522000451 is an equidigital number, since it uses as much as digits as its factorization.

133305522000451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54000, while the sum is 34.

Adding to 133305522000451 its reverse (154000225503331), we get a palindrome (287305747503782).

The spelling of 133305522000451 in words is "one hundred thirty-three trillion, three hundred five billion, five hundred twenty-two million, four hundred fifty-one", and thus it is an aban number.