Base | Representation |
---|---|
bin | 11110010011111010101000… |
… | …011100101000001011011111 |
3 | 122111000022110120111122120212 |
4 | 132103322220130220023133 |
5 | 114433122410334311033 |
6 | 1151305440031403035 |
7 | 40036221411110225 |
oct | 3623725034501337 |
9 | 574008416448525 |
10 | 133310021010143 |
11 | 3952750a52546a |
12 | 12b5046038347b |
13 | 5950109079293 |
14 | 24cc34d068b15 |
15 | 1062a76109748 |
hex | 793ea87282df |
133310021010143 has 2 divisors, whose sum is σ = 133310021010144. Its totient is φ = 133310021010142.
The previous prime is 133310021010097. The next prime is 133310021010151. The reversal of 133310021010143 is 341010120013331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133310021010143 - 26 = 133310021010079 is a prime.
It is a super-2 number, since 2×1333100210101432 (a number of 29 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133310021010443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66655010505071 + 66655010505072.
It is an arithmetic number, because the mean of its divisors is an integer number (66655010505072).
Almost surely, 2133310021010143 is an apocalyptic number.
133310021010143 is a deficient number, since it is larger than the sum of its proper divisors (1).
133310021010143 is an equidigital number, since it uses as much as digits as its factorization.
133310021010143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 133310021010143 its reverse (341010120013331), we get a palindrome (474320141023474).
The spelling of 133310021010143 in words is "one hundred thirty-three trillion, three hundred ten billion, twenty-one million, ten thousand, one hundred forty-three".
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