Base | Representation |
---|---|
bin | 1100000111111101111010… |
… | …1110000000010000101110 |
3 | 1202012102200201020222111221 |
4 | 3001333132232000100232 |
5 | 3221403412122334014 |
6 | 44204104110333554 |
7 | 2544064051246012 |
oct | 301773656002056 |
9 | 52172621228457 |
10 | 13331020121134 |
11 | 427a721357141 |
12 | 15b37837ba2ba |
13 | 759157312891 |
14 | 341320c7a542 |
15 | 181b852c7b24 |
hex | c1fdeb8042e |
13331020121134 has 4 divisors (see below), whose sum is σ = 19996530181704. Its totient is φ = 6665510060566.
The previous prime is 13331020121113. The next prime is 13331020121149. The reversal of 13331020121134 is 43112102013331.
13331020121134 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 13331020121099 and 13331020121108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3332755030282 + ... + 3332755030285.
It is an arithmetic number, because the mean of its divisors is an integer number (4999132545426).
Almost surely, 213331020121134 is an apocalyptic number.
13331020121134 is a deficient number, since it is larger than the sum of its proper divisors (6665510060570).
13331020121134 is an equidigital number, since it uses as much as digits as its factorization.
13331020121134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6665510060569.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13331020121134 its reverse (43112102013331), we get a palindrome (56443122134465).
The spelling of 13331020121134 in words is "thirteen trillion, three hundred thirty-one billion, twenty million, one hundred twenty-one thousand, one hundred thirty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •