Base | Representation |
---|---|
bin | 10011011001100011101… |
… | …011001000011101101001 |
3 | 11201102222212122002001202 |
4 | 103121203223020131221 |
5 | 133320203200104001 |
6 | 2500231231053545 |
7 | 165212521665104 |
oct | 23314353103551 |
9 | 4642885562052 |
10 | 1333112113001 |
11 | 474408040839 |
12 | 1964486712b5 |
13 | 98934168b06 |
14 | 4874706173b |
15 | 24a25d8b96b |
hex | 13663ac8769 |
1333112113001 has 2 divisors, whose sum is σ = 1333112113002. Its totient is φ = 1333112113000.
The previous prime is 1333112112973. The next prime is 1333112113051. The reversal of 1333112113001 is 1003112113331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1186304358976 + 146807754025 = 1089176^2 + 383155^2 .
It is an emirp because it is prime and its reverse (1003112113331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1333112113001 is a prime.
It is not a weakly prime, because it can be changed into another prime (1333112113051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666556056500 + 666556056501.
It is an arithmetic number, because the mean of its divisors is an integer number (666556056501).
Almost surely, 21333112113001 is an apocalyptic number.
It is an amenable number.
1333112113001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1333112113001 is an equidigital number, since it uses as much as digits as its factorization.
1333112113001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 1333112113001 its reverse (1003112113331), we get a palindrome (2336224226332).
The spelling of 1333112113001 in words is "one trillion, three hundred thirty-three billion, one hundred twelve million, one hundred thirteen thousand, one".
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