Base | Representation |
---|---|
bin | 10011011001100011101… |
… | …011001000011101101000 |
3 | 11201102222212122002001201 |
4 | 103121203223020131220 |
5 | 133320203200104000 |
6 | 2500231231053544 |
7 | 165212521665103 |
oct | 23314353103550 |
9 | 4642885562051 |
10 | 1333112113000 |
11 | 474408040838 |
12 | 1964486712b4 |
13 | 98934168b05 |
14 | 4874706173a |
15 | 24a25d8b96a |
hex | 13663ac8768 |
1333112113000 has 64 divisors (see below), whose sum is σ = 3119979704400. Its totient is φ = 533159827200.
The previous prime is 1333112112973. The next prime is 1333112113001. The reversal of 1333112113000 is 3112113331.
It can be written as a sum of positive squares in 8 ways, for example, as 79791560676 + 1253320552324 = 282474^2 + 1119518^2 .
It is not an unprimeable number, because it can be changed into a prime (1333112113001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6365962 + ... + 6572038.
Almost surely, 21333112113000 is an apocalyptic number.
1333112113000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1333112113000 is an abundant number, since it is smaller than the sum of its proper divisors (1786867591400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1333112113000 is a wasteful number, since it uses less digits than its factorization.
1333112113000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 212567 (or 212553 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 1333112113000 its reverse (3112113331), we get a palindrome (1336224226331).
The spelling of 1333112113000 in words is "one trillion, three hundred thirty-three billion, one hundred twelve million, one hundred thirteen thousand".
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