Base | Representation |
---|---|
bin | 10011011001100011101… |
… | …011100010100101110001 |
3 | 11201102222212211111212022 |
4 | 103121203223202211301 |
5 | 133320203212020032 |
6 | 2500231233241225 |
7 | 165212522622104 |
oct | 23314353424561 |
9 | 4642885744768 |
10 | 1333112220017 |
11 | 474408104186 |
12 | 196448703215 |
13 | 989341a5736 |
14 | 4874708c73b |
15 | 24a25dad512 |
hex | 13663ae2971 |
1333112220017 has 2 divisors, whose sum is σ = 1333112220018. Its totient is φ = 1333112220016.
The previous prime is 1333112219983. The next prime is 1333112220019. The reversal of 1333112220017 is 7100222113331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1026363505216 + 306748714801 = 1013096^2 + 553849^2 .
It is a cyclic number.
It is not a de Polignac number, because 1333112220017 - 26 = 1333112219953 is a prime.
Together with 1333112220019, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1333112220019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666556110008 + 666556110009.
It is an arithmetic number, because the mean of its divisors is an integer number (666556110009).
Almost surely, 21333112220017 is an apocalyptic number.
It is an amenable number.
1333112220017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1333112220017 is an equidigital number, since it uses as much as digits as its factorization.
1333112220017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 26.
Adding to 1333112220017 its reverse (7100222113331), we get a palindrome (8433334333348).
The spelling of 1333112220017 in words is "one trillion, three hundred thirty-three billion, one hundred twelve million, two hundred twenty thousand, seventeen".
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