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133311331103 is a prime number
BaseRepresentation
bin111110000100111111…
…0010111101100011111
3110202002200210021221112
41330021332113230133
54141010200043403
6141124204252235
712426402421616
oct1741176275437
9422080707845
10133311331103
115159a853205
1221a0584107b
13c756c23552
14664919487d
1537039039d8
hex1f09f97b1f

133311331103 has 2 divisors, whose sum is σ = 133311331104. Its totient is φ = 133311331102.

The previous prime is 133311331081. The next prime is 133311331141. The reversal of 133311331103 is 301133113331.

It is a weak prime.

It is an emirp because it is prime and its reverse (301133113331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133311331103 - 222 = 133307136799 is a prime.

It is a super-2 number, since 2×1333113311032 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133311331003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66655665551 + 66655665552.

It is an arithmetic number, because the mean of its divisors is an integer number (66655665552).

Almost surely, 2133311331103 is an apocalyptic number.

133311331103 is a deficient number, since it is larger than the sum of its proper divisors (1).

133311331103 is an equidigital number, since it uses as much as digits as its factorization.

133311331103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 729, while the sum is 23.

Adding to 133311331103 its reverse (301133113331), we get a palindrome (434444444434).

The spelling of 133311331103 in words is "one hundred thirty-three billion, three hundred eleven million, three hundred thirty-one thousand, one hundred three".