Base | Representation |
---|---|
bin | 10011011001100011110… |
… | …011001101011010100010 |
3 | 11201110000000121122122012 |
4 | 103121203303031122202 |
5 | 133320204220333214 |
6 | 2500231344312522 |
7 | 165212545664300 |
oct | 23314363153242 |
9 | 4643000548565 |
10 | 1333114230434 |
11 | 474409257688 |
12 | 196449312742 |
13 | 9893472a82c |
14 | 48747453270 |
15 | 24a2615903e |
hex | 13663ccd6a2 |
1333114230434 has 12 divisors (see below), whose sum is σ = 2326148300214. Its totient is φ = 571334670144.
The previous prime is 1333114230361. The next prime is 1333114230529. The reversal of 1333114230434 is 4340324113331.
It is a happy number.
It can be written as a sum of positive squares in only one way, i.e., 1082817142225 + 250297088209 = 1040585^2 + 500297^2 .
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 1333114230434.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6801603119 + ... + 6801603314.
Almost surely, 21333114230434 is an apocalyptic number.
1333114230434 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
1333114230434 is a deficient number, since it is larger than the sum of its proper divisors (993034069780).
1333114230434 is a wasteful number, since it uses less digits than its factorization.
1333114230434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13603206449 (or 13603206442 counting only the distinct ones).
The product of its (nonzero) digits is 31104, while the sum is 32.
Adding to 1333114230434 its reverse (4340324113331), we get a palindrome (5673438343765).
The spelling of 1333114230434 in words is "one trillion, three hundred thirty-three billion, one hundred fourteen million, two hundred thirty thousand, four hundred thirty-four".
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