Base | Representation |
---|---|
bin | 10011011001100100110… |
… | …011101010110111001101 |
3 | 11201110001012102011002221 |
4 | 103121210303222313031 |
5 | 133320223032101034 |
6 | 2500233150415341 |
7 | 165213142423153 |
oct | 23314463526715 |
9 | 4643035364087 |
10 | 1333131128269 |
11 | 474417849236 |
12 | 196452b01551 |
13 | 98938095c55 |
14 | 487497b13d3 |
15 | 24a27895bb4 |
hex | 13664ceadcd |
1333131128269 has 2 divisors, whose sum is σ = 1333131128270. Its totient is φ = 1333131128268.
The previous prime is 1333131128207. The next prime is 1333131128299. The reversal of 1333131128269 is 9628211313331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 811647837225 + 521483291044 = 900915^2 + 722138^2 .
It is a cyclic number.
It is not a de Polignac number, because 1333131128269 - 215 = 1333131095501 is a prime.
It is a super-2 number, since 2×13331311282692 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1333131128299) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666565564134 + 666565564135.
It is an arithmetic number, because the mean of its divisors is an integer number (666565564135).
Almost surely, 21333131128269 is an apocalyptic number.
It is an amenable number.
1333131128269 is a deficient number, since it is larger than the sum of its proper divisors (1).
1333131128269 is an equidigital number, since it uses as much as digits as its factorization.
1333131128269 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 139968, while the sum is 43.
The spelling of 1333131128269 in words is "one trillion, three hundred thirty-three billion, one hundred thirty-one million, one hundred twenty-eight thousand, two hundred sixty-nine".
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