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133313232242401 is a prime number
BaseRepresentation
bin11110010011111101100111…
…110110100000011011100001
3122111000121202101000011002221
4132103331213312200123201
5114433200444423224101
61151311130423311041
740036364113121341
oct3623754766403341
9574017671004087
10133313232242401
113952890814a822
1212b50bb78ab481
1359504cb44b503
1424cc575738d21
151062bb2ec5aa1
hex793f67da06e1

133313232242401 has 2 divisors, whose sum is σ = 133313232242402. Its totient is φ = 133313232242400.

The previous prime is 133313232242383. The next prime is 133313232242441. The reversal of 133313232242401 is 104242232313331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100422445210000 + 32890787032401 = 10021100^2 + 5735049^2 .

It is a cyclic number.

It is not a de Polignac number, because 133313232242401 - 217 = 133313232111329 is a prime.

It is a super-3 number, since 3×1333132322424013 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (133313232242441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66656616121200 + 66656616121201.

It is an arithmetic number, because the mean of its divisors is an integer number (66656616121201).

Almost surely, 2133313232242401 is an apocalyptic number.

It is an amenable number.

133313232242401 is a deficient number, since it is larger than the sum of its proper divisors (1).

133313232242401 is an equidigital number, since it uses as much as digits as its factorization.

133313232242401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 62208, while the sum is 34.

Adding to 133313232242401 its reverse (104242232313331), we get a palindrome (237555464555732).

The spelling of 133313232242401 in words is "one hundred thirty-three trillion, three hundred thirteen billion, two hundred thirty-two million, two hundred forty-two thousand, four hundred one".