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13331412043 is a prime number
BaseRepresentation
bin11000110101001110…
…10011010001001011
31021102002101220022121
430122213103101023
5204300320141133
610042510232111
7651236063335
oct143247232113
937362356277
1013331412043
115721264204
1227007b5637
131345c4a3c1
14906798455
155305b802d
hex31a9d344b

13331412043 has 2 divisors, whose sum is σ = 13331412044. Its totient is φ = 13331412042.

The previous prime is 13331412037. The next prime is 13331412071. The reversal of 13331412043 is 34021413331.

13331412043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13331412043 - 213 = 13331403851 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13331411999 and 13331412017.

It is not a weakly prime, because it can be changed into another prime (13331412443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665706021 + 6665706022.

It is an arithmetic number, because the mean of its divisors is an integer number (6665706022).

Almost surely, 213331412043 is an apocalyptic number.

13331412043 is a deficient number, since it is larger than the sum of its proper divisors (1).

13331412043 is an equidigital number, since it uses as much as digits as its factorization.

13331412043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13331412043 its reverse (34021413331), we get a palindrome (47352825374).

The spelling of 13331412043 in words is "thirteen billion, three hundred thirty-one million, four hundred twelve thousand, forty-three".