Base | Representation |
---|---|
bin | 1100000111111111011000… |
… | …1001100011101100101111 |
3 | 1202012110201002221110222111 |
4 | 3001333312021203230233 |
5 | 3221410213241021033 |
6 | 44204211112024451 |
7 | 2544106563446164 |
oct | 301776611435457 |
9 | 52173632843874 |
10 | 13331413220143 |
11 | 427a903239257 |
12 | 15b3873392127 |
13 | 7591ba8a9045 |
14 | 34135b16606b |
15 | 181ba9a767cd |
hex | c1ff6263b2f |
13331413220143 has 2 divisors, whose sum is σ = 13331413220144. Its totient is φ = 13331413220142.
The previous prime is 13331413220137. The next prime is 13331413220171. The reversal of 13331413220143 is 34102231413331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13331413220143 - 213 = 13331413211951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13331413220243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665706610071 + 6665706610072.
It is an arithmetic number, because the mean of its divisors is an integer number (6665706610072).
Almost surely, 213331413220143 is an apocalyptic number.
13331413220143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13331413220143 is an equidigital number, since it uses as much as digits as its factorization.
13331413220143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 13331413220143 its reverse (34102231413331), we get a palindrome (47433644633474).
The spelling of 13331413220143 in words is "thirteen trillion, three hundred thirty-one billion, four hundred thirteen million, two hundred twenty thousand, one hundred forty-three".
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