13331413234039 has 2 divisors, whose sum is σ = 13331413234040. Its totient is φ = 13331413234038.

The previous prime is 13331413234019. The next prime is 13331413234043. The reversal of 13331413234039 is 93043231413331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13331413234039 - 2⁷ = 13331413233911 is a prime.

It is a super-3 number, since 3×13331413234039³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13331413233992 and 13331413234010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13331413234019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665706617019 + 6665706617020.

It is an arithmetic number, because the mean of its divisors is an integer number (6665706617020).

Almost surely, 2^{13331413234039} is an apocalyptic number.

13331413234039 is a deficient number, since it is larger than the sum of its proper divisors (1).

13331413234039 is an equidigital number, since it uses as much as digits as its factorization.

13331413234039 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 209952, while the sum is 40.

The spelling of 13331413234039 in words is "thirteen trillion, three hundred thirty-one billion, four hundred thirteen million, two hundred thirty-four thousand, thirty-nine".