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133320000041 is a prime number
BaseRepresentation
bin111110000101001111…
…1011100001000101001
3110202010022002201111022
41330022133130020221
54141014410000131
6141125114142225
712426536205524
oct1741237341051
9422108081438
10133320000041
11515a4734318
1221a08721975
13c75896a2b7
14664a3adbbb
15370456737b
hex1f0a7dc229

133320000041 has 2 divisors, whose sum is σ = 133320000042. Its totient is φ = 133320000040.

The previous prime is 133320000019. The next prime is 133320000059. The reversal of 133320000041 is 140000023331.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70830499600 + 62489500441 = 266140^2 + 249979^2 .

It is a cyclic number.

It is not a de Polignac number, because 133320000041 - 218 = 133319737897 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 133319999974 and 133320000019.

It is not a weakly prime, because it can be changed into another prime (133320000001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66660000020 + 66660000021.

It is an arithmetic number, because the mean of its divisors is an integer number (66660000021).

Almost surely, 2133320000041 is an apocalyptic number.

It is an amenable number.

133320000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

133320000041 is an equidigital number, since it uses as much as digits as its factorization.

133320000041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 133320000041 its reverse (140000023331), we get a palindrome (273320023372).

The spelling of 133320000041 in words is "one hundred thirty-three billion, three hundred twenty million, forty-one", and thus it is an aban number.