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13332012403 is a prime number
BaseRepresentation
bin11000110101010011…
…00101110101110011
31021102010112101212011
430122221211311303
5204300443344103
610042531143351
7651244143553
oct143251456563
937363471764
1013332012403
115721634276
122700a44b57
1313460ca748
149068b3163
15530685d6d
hex31aa65d73

13332012403 has 2 divisors, whose sum is σ = 13332012404. Its totient is φ = 13332012402.

The previous prime is 13332012401. The next prime is 13332012409. The reversal of 13332012403 is 30421023331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13332012403 - 21 = 13332012401 is a prime.

Together with 13332012401, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13332012401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666006201 + 6666006202.

It is an arithmetic number, because the mean of its divisors is an integer number (6666006202).

Almost surely, 213332012403 is an apocalyptic number.

13332012403 is a deficient number, since it is larger than the sum of its proper divisors (1).

13332012403 is an equidigital number, since it uses as much as digits as its factorization.

13332012403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 13332012403 its reverse (30421023331), we get a palindrome (43753035734).

The spelling of 13332012403 in words is "thirteen billion, three hundred thirty-two million, twelve thousand, four hundred three".