Base | Representation |
---|---|
bin | 1100001000000001100111… |
… | …1010000010000110000001 |
3 | 1202012112020220210001202021 |
4 | 3002000121322002012001 |
5 | 3221412430330130423 |
6 | 44204350422121441 |
7 | 2544130466551636 |
oct | 302003172020601 |
9 | 52175226701667 |
10 | 13332013130113 |
11 | 4280090935517 |
12 | 15b3a00280281 |
13 | 759284c72962 |
14 | 3413b6ac818d |
15 | 181be257795d |
hex | c2019e82181 |
13332013130113 has 2 divisors, whose sum is σ = 13332013130114. Its totient is φ = 13332013130112.
The previous prime is 13332013130087. The next prime is 13332013130201. The reversal of 13332013130113 is 31103131023331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6984349555264 + 6347663574849 = 2642792^2 + 2519457^2 .
It is a cyclic number.
It is not a de Polignac number, because 13332013130113 - 29 = 13332013129601 is a prime.
It is not a weakly prime, because it can be changed into another prime (13332013130713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666006565056 + 6666006565057.
It is an arithmetic number, because the mean of its divisors is an integer number (6666006565057).
Almost surely, 213332013130113 is an apocalyptic number.
It is an amenable number.
13332013130113 is a deficient number, since it is larger than the sum of its proper divisors (1).
13332013130113 is an equidigital number, since it uses as much as digits as its factorization.
13332013130113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 13332013130113 its reverse (31103131023331), we get a palindrome (44435144153444).
The spelling of 13332013130113 in words is "thirteen trillion, three hundred thirty-two billion, thirteen million, one hundred thirty thousand, one hundred thirteen".
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