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13332013130113 is a prime number
BaseRepresentation
bin1100001000000001100111…
…1010000010000110000001
31202012112020220210001202021
43002000121322002012001
53221412430330130423
644204350422121441
72544130466551636
oct302003172020601
952175226701667
1013332013130113
114280090935517
1215b3a00280281
13759284c72962
143413b6ac818d
15181be257795d
hexc2019e82181

13332013130113 has 2 divisors, whose sum is σ = 13332013130114. Its totient is φ = 13332013130112.

The previous prime is 13332013130087. The next prime is 13332013130201. The reversal of 13332013130113 is 31103131023331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6984349555264 + 6347663574849 = 2642792^2 + 2519457^2 .

It is a cyclic number.

It is not a de Polignac number, because 13332013130113 - 29 = 13332013129601 is a prime.

It is not a weakly prime, because it can be changed into another prime (13332013130713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666006565056 + 6666006565057.

It is an arithmetic number, because the mean of its divisors is an integer number (6666006565057).

Almost surely, 213332013130113 is an apocalyptic number.

It is an amenable number.

13332013130113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13332013130113 is an equidigital number, since it uses as much as digits as its factorization.

13332013130113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 13332013130113 its reverse (31103131023331), we get a palindrome (44435144153444).

The spelling of 13332013130113 in words is "thirteen trillion, three hundred thirty-two billion, thirteen million, one hundred thirty thousand, one hundred thirteen".