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13332034322197 is a prime number
BaseRepresentation
bin1100001000000001101100…
…1010110111111100010101
31202012112022101122201211021
43002000123022313330111
53221413001241302242
644204352500241141
72544131144644303
oct302003312677425
952175271581737
1013332034322197
1142800a189a438
1215b3a073a01b1
13759289482856
143413b9843273
15181be4361b67
hexc201b2b7f15

13332034322197 has 2 divisors, whose sum is σ = 13332034322198. Its totient is φ = 13332034322196.

The previous prime is 13332034322179. The next prime is 13332034322227. The reversal of 13332034322197 is 79122343023331.

Together with previous prime (13332034322179) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8497493182116 + 4834541140081 = 2915046^2 + 2198759^2 .

It is a cyclic number.

It is not a de Polignac number, because 13332034322197 - 215 = 13332034289429 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13332034322177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666017161098 + 6666017161099.

It is an arithmetic number, because the mean of its divisors is an integer number (6666017161099).

Almost surely, 213332034322197 is an apocalyptic number.

It is an amenable number.

13332034322197 is a deficient number, since it is larger than the sum of its proper divisors (1).

13332034322197 is an equidigital number, since it uses as much as digits as its factorization.

13332034322197 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 489888, while the sum is 43.

The spelling of 13332034322197 in words is "thirteen trillion, three hundred thirty-two billion, thirty-four million, three hundred twenty-two thousand, one hundred ninety-seven".