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133320444014 = 266660222007
BaseRepresentation
bin111110000101010000…
…1001000100001101110
3110202010022221021111202
41330022201020201232
54141020013202024
6141125131445502
712426543035102
oct1741241104156
9422108837452
10133320444014
11515a4a0793a
1221a088b6892
13c758a943c4
14664a487902
153704603bae
hex1f0a84886e

133320444014 has 4 divisors (see below), whose sum is σ = 199980666024. Its totient is φ = 66660222006.

The previous prime is 133320443959. The next prime is 133320444073. The reversal of 133320444014 is 410444023331.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 410444023331 = 1606925542599.

It is a super-3 number, since 3×1333204440143 (a number of 34 digits) contains 333 as substring.

It is a Curzon number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33330111002 + ... + 33330111005.

It is an arithmetic number, because the mean of its divisors is an integer number (49995166506).

Almost surely, 2133320444014 is an apocalyptic number.

133320444014 is a deficient number, since it is larger than the sum of its proper divisors (66660222010).

133320444014 is an equidigital number, since it uses as much as digits as its factorization.

133320444014 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66660222009.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 133320444014 its reverse (410444023331), we get a palindrome (543764467345).

The spelling of 133320444014 in words is "one hundred thirty-three billion, three hundred twenty million, four hundred forty-four thousand, fourteen".

Divisors: 1 2 66660222007 133320444014