Base | Representation |
---|---|
bin | 11110010100000100111000… |
… | …001110010110011100110111 |
3 | 122111001100212022220210122211 |
4 | 132110010320032112130313 |
5 | 114433312423404334312 |
6 | 1151314455453034251 |
7 | 40040061144364615 |
oct | 3624047016263467 |
9 | 574040768823584 |
10 | 133321023121207 |
11 | 39531145975339 |
12 | 12b52610a85987 |
13 | 595117056277c |
14 | 24ccab43286b5 |
15 | 1062ebbe643a7 |
hex | 794138396737 |
133321023121207 has 2 divisors, whose sum is σ = 133321023121208. Its totient is φ = 133321023121206.
The previous prime is 133321023121189. The next prime is 133321023121229. The reversal of 133321023121207 is 702121320123331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133321023121207 - 223 = 133321014732599 is a prime.
It is a super-2 number, since 2×1333210231212072 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133321023125207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66660511560603 + 66660511560604.
It is an arithmetic number, because the mean of its divisors is an integer number (66660511560604).
Almost surely, 2133321023121207 is an apocalyptic number.
133321023121207 is a deficient number, since it is larger than the sum of its proper divisors (1).
133321023121207 is an equidigital number, since it uses as much as digits as its factorization.
133321023121207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 31.
Adding to 133321023121207 its reverse (702121320123331), we get a palindrome (835442343244538).
The spelling of 133321023121207 in words is "one hundred thirty-three trillion, three hundred twenty-one billion, twenty-three million, one hundred twenty-one thousand, two hundred seven".
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