Base | Representation |
---|---|
bin | 1100001000000010000001… |
… | …0110010010010110000000 |
3 | 1202012112112110010120202200 |
4 | 3002000200112102112000 |
5 | 3221413141011400000 |
6 | 44204405242313200 |
7 | 2544133251254331 |
oct | 302004026222600 |
9 | 52175473116680 |
10 | 13332121200000 |
11 | 4280136938a79 |
12 | 15b3a304b8800 |
13 | 7592a1480635 |
14 | 3413c71ba288 |
15 | 181bebcc3500 |
hex | c2020592580 |
13332121200000 has 1152 divisors, whose sum is σ = 49786455962880. Its totient is φ = 3421440000000.
The previous prime is 13332121199981. The next prime is 13332121200103. The reversal of 13332121200000 is 212123331.
13332121200000 is a `hidden beast` number, since 1 + 333 + 212 + 120 + 0 + 0 + 0 + 0 = 666.
It is a tau number, because it is divible by the number of its divisors (1152).
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 13453199505 + ... + 13453200495.
It is an arithmetic number, because the mean of its divisors is an integer number (43217409690).
Almost surely, 213332121200000 is an apocalyptic number.
13332121200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13332121200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24893227981440).
13332121200000 is an abundant number, since it is smaller than the sum of its proper divisors (36454334762880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13332121200000 is an equidigital number, since it uses as much as digits as its factorization.
13332121200000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1174 (or 1139 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 13332121200000 its reverse (212123331), we get a palindrome (13332333323331).
The spelling of 13332121200000 in words is "thirteen trillion, three hundred thirty-two billion, one hundred twenty-one million, two hundred thousand".
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