13332122147 has 2 divisors, whose sum is σ = 13332122148. Its totient is φ = 13332122146.

The previous prime is 13332122113. The next prime is 13332122149. The reversal of 13332122147 is 74122123331.

It is a strong prime.

It is an emirp because it is prime and its reverse (74122123331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13332122147 is a prime.

Together with 13332122149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13332122149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666061073 + 6666061074.

It is an arithmetic number, because the mean of its divisors is an integer number (6666061074).

Almost surely, 2^13332122147 is an apocalyptic number.

13332122147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13332122147 is an equidigital number, since it uses as much as digits as its factorization.

13332122147 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6048, while the sum is 29.

Adding to 13332122147 its reverse (74122123331), we get a palindrome (87454245478).

The spelling of 13332122147 in words is "thirteen billion, three hundred thirty-two million, one hundred twenty-two thousand, one hundred forty-seven".