Base | Representation |
---|---|
bin | 11000110101010100… |
… | …11110101111000001 |
3 | 1021102010222020112012 |
4 | 30122222132233001 |
5 | 204301023323231 |
6 | 10042540142305 |
7 | 651246134144 |
oct | 143252365701 |
9 | 37363866465 |
10 | 13332245441 |
11 | 5721783369 |
12 | 2700b37995 |
13 | 134617c838 |
14 | 90693405b |
15 | 5306cee2b |
hex | 31aa9ebc1 |
13332245441 has 2 divisors, whose sum is σ = 13332245442. Its totient is φ = 13332245440.
The previous prime is 13332245431. The next prime is 13332245533. The reversal of 13332245441 is 14454223331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10711215025 + 2621030416 = 103495^2 + 51196^2 .
It is a cyclic number.
It is not a de Polignac number, because 13332245441 - 210 = 13332244417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13332245398 and 13332245407.
It is not a weakly prime, because it can be changed into another prime (13332245411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666122720 + 6666122721.
It is an arithmetic number, because the mean of its divisors is an integer number (6666122721).
Almost surely, 213332245441 is an apocalyptic number.
It is an amenable number.
13332245441 is a deficient number, since it is larger than the sum of its proper divisors (1).
13332245441 is an equidigital number, since it uses as much as digits as its factorization.
13332245441 is an evil number, because the sum of its binary digits is even.
The product of its digits is 34560, while the sum is 32.
Adding to 13332245441 its reverse (14454223331), we get a palindrome (27786468772).
The spelling of 13332245441 in words is "thirteen billion, three hundred thirty-two million, two hundred forty-five thousand, four hundred forty-one".
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