Base | Representation |
---|---|
bin | 1100001000000010101100… |
… | …0001111011001001011001 |
3 | 1202012112222221100110200221 |
4 | 3002000223001323021121 |
5 | 3221414022401131411 |
6 | 44204435123400041 |
7 | 2544140555446642 |
oct | 302005301731131 |
9 | 52175887313627 |
10 | 13332300411481 |
11 | 4280219012237 |
12 | 15b3a80523021 |
13 | 7592cc63962c |
14 | 341402d0a6c9 |
15 | 181c0c8c3071 |
hex | c202b07b259 |
13332300411481 has 2 divisors, whose sum is σ = 13332300411482. Its totient is φ = 13332300411480.
The previous prime is 13332300411383. The next prime is 13332300411487. The reversal of 13332300411481 is 18411400323331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11862920059081 + 1469380352400 = 3444259^2 + 1212180^2 .
It is a cyclic number.
It is not a de Polignac number, because 13332300411481 - 29 = 13332300410969 is a prime.
It is a super-2 number, since 2×133323004114812 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13332300411487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666150205740 + 6666150205741.
It is an arithmetic number, because the mean of its divisors is an integer number (6666150205741).
Almost surely, 213332300411481 is an apocalyptic number.
It is an amenable number.
13332300411481 is a deficient number, since it is larger than the sum of its proper divisors (1).
13332300411481 is an equidigital number, since it uses as much as digits as its factorization.
13332300411481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 34.
The spelling of 13332300411481 in words is "thirteen trillion, three hundred thirty-two billion, three hundred million, four hundred eleven thousand, four hundred eighty-one".
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