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13332300411481 is a prime number
BaseRepresentation
bin1100001000000010101100…
…0001111011001001011001
31202012112222221100110200221
43002000223001323021121
53221414022401131411
644204435123400041
72544140555446642
oct302005301731131
952175887313627
1013332300411481
114280219012237
1215b3a80523021
137592cc63962c
14341402d0a6c9
15181c0c8c3071
hexc202b07b259

13332300411481 has 2 divisors, whose sum is σ = 13332300411482. Its totient is φ = 13332300411480.

The previous prime is 13332300411383. The next prime is 13332300411487. The reversal of 13332300411481 is 18411400323331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11862920059081 + 1469380352400 = 3444259^2 + 1212180^2 .

It is a cyclic number.

It is not a de Polignac number, because 13332300411481 - 29 = 13332300410969 is a prime.

It is a super-2 number, since 2×133323004114812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13332300411487) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666150205740 + 6666150205741.

It is an arithmetic number, because the mean of its divisors is an integer number (6666150205741).

Almost surely, 213332300411481 is an apocalyptic number.

It is an amenable number.

13332300411481 is a deficient number, since it is larger than the sum of its proper divisors (1).

13332300411481 is an equidigital number, since it uses as much as digits as its factorization.

13332300411481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 34.

The spelling of 13332300411481 in words is "thirteen trillion, three hundred thirty-two billion, three hundred million, four hundred eleven thousand, four hundred eighty-one".